Determine the value of \sin 1110\degree

Collected in the board: Trigonometry

Steven Zheng posted 5 months ago


Since the sines function has a period of 360\degree, \sin 1110\degree is equal to sines of its remainder after divided by the period.

\because 1110 \mod 360=30

\therefore \sin 1110\degree=\sin 30\degree =\dfrac{1}{2}

Steven Zheng posted 3 months ago

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