If $$\sin heta \geq \dfrac{\sqrt{3} }{2}$$, determine the domain of $$ heta$$ in a unit circle

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If $$\sin 	heta \geq  \dfrac{\sqrt{3}  }{2}$$, determine the domain of $$	heta$$ in a unit circle

Uniteasy Admin · Accepted Answer

If $$\sin 	heta \geq \dfrac{\sqrt{3} }{2}$$, $$	heta$$ is in the domain of 
$$\dfrac{\pi}{3}  \leq 	heta \leq \dfrac{2\pi}{3} $$
First construct the angle $$\dfrac{\pi}{3} $$ in the unit circle
And then construct the angle of $$ \dfrac{2\pi}{3} $$
The domain of $$	heta$$ is the area between the two angles

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