Filling Question
\sin^2(42\degree +\alpha ) +\cot(25\degree +\beta )\cdotp \cot (\beta -65\degree )+\sin^2(48\degree -\alpha ) =
\sin^2(42\degree +\alpha ) +\cot(25\degree +\beta )\cdotp \cot (\beta -65\degree )+\sin^2(48\degree -\alpha ) =
Apply Pythagorean Identity and cofucntion identity
\sin^2(42\degree +\alpha ) +\cot(25\degree +\beta )\cdotp \cot (\beta -65\degree )+\sin^2(48\degree -\alpha )
=\sin^2(42\degree +\alpha ) +\sin^2[90\degree -(\alpha+42\degree ) ]+\cot(90\degree-65\degree +\beta )\cdotp \cot (\beta -65\degree )
=\sin^2(42\degree +\alpha ) +\cos^2(42\degree +\alpha ) -\tan(\beta-65\degree )\cdotp \cot (\beta -65\degree )
=1-1=0