10\sqrt[3]{8} and 5\sqrt[3]{27} are not like radicals as they have different radicands 8 and 27. However, their radicands are perfect cube numbers.

So we can take out the perfect cube numbers inside the radical symbol first.

10\sqrt[3]{8}-5\sqrt[3]{27} = 10\times 2-5\times 3 = 5

Steven Zheng Steven Zheng posted 2 weeks ago

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