Suppose that you play black jack at Harrah's on June 1 and lose $1,000. Tomorrow you bet and lose$15 less. Each day you lose $15 less that your previous loss. What will your total losses be for the 30 days of June? Collected in the board: Arithmetic sequence Steven Zheng posted 5 months ago #### Answer As each day you lose$15 less that your previous loss, this is an arithmetic sequence and the difference between any two successive terms is -15. So,

a_1=1000

and

d=-15

The formula for general terms is

a_n=a_1+(n-1)d = 1000+(n-1)(-15) = -15n+1015

a_{30} = -15(30)+1015=565

Calculate the 30th partial sum as follows:

S_{30} = \dfrac{30(a_1+a_{30})}{2}=\dfrac{30(1000+565)}{2}=23475

So after 30 days you will lose a total of \$23,475

Steven Zheng posted 5 months ago

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