The parabola with the equation $$y=4x-\dfrac{1}{2}x^2$$ has how many points with $$(x,y)$$ coordinates that are both positive integers?

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Uniteasy Admin · Accepted Answer

If $$y>0$$, $$4x-\dfrac{1}{2}x^2>0$$ $$x(8-x)>0$$ $$x(x-8)<0$$ $$ herefore 0 < x<8 $$ $$\because y = 4x-\dfrac{1}{2}x^2$$ In order for $$y$$ to be integers, $$x$$ must be even numbers. So $$x $$could be 2, 4, 6 A is the choice.

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