If $$ f(x)=x^2-1 $$ , $$ g(x)=(x-1)^{-1}, $$ and $$ x {=}\mathllap{/\,}1 $$ , then $$ f(x)g(x) = $$

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Uniteasy Admin · Accepted Answer

Factorize the function $$ f(x) $$

$$ f(x)= x^2-1 = (x+1)(x-1) $$

So the product of the two functions
$$ f(x)g(x) = (x+1)(x-1)\cdotp \dfrac{1}{x-1} = x+1 $$

Multiple Choice Question (MCQ)

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