In the figure, the area of quadrilateral $$ ABCD $$ is

Question

Uniteasy Admin · Accepted Answer

Since $$ 	riangle ABD  $$ is a right triangle,

$$ BD = \sqrt{3^2+4^2}  =5 $$

$$ \because 13^2 = 12^2+5^2 =169  $$

 The measure of three sides of $$ 	riangle BCD $$ has the following relationship
$$ BC^2 = BD^2+CD^2 $$
Therefore,  $$ 	riangle BCD $$ is also a right triangle.

So the area of quadrilateral ABCD  is,
$$ A_{ABCD}  =A_{	riangle ABD }+A_{	riangle BCD } $$
$$ =\dfrac{1}{2}\cdotp 3\cdotp 4+\dfrac{1}{2}\cdotp 5\cdotp 12 $$
$$ =36 $$

Multiple Choice Question (MCQ)

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