Multiple Choice Question (MCQ)

Simplify the algebraic expression (\dfrac{a^2}{a-3}+\dfrac{9}{3-a})÷\dfrac{a+3}{a} , it’s result is

  1. ×

    -a

  2. a

  3. ×

    \dfrac{(a+3)^2}{a}

  4. ×

    1

Collected in the board: Fractions

Steven Zheng posted 1 year ago


Answer

  1. (\dfrac{a^2}{a-3}+\dfrac{9}{3-a})÷\dfrac{a+3}{a}

    =(\dfrac{a^2-9}{a-3})\cdotp \dfrac{a}{a+3}

    =\dfrac{(a+3)(a-3)}{a-3}\cdotp \dfrac{a}{a+3}

    =a

Steven Zheng posted 1 month ago

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