Selective Question

Simply \dfrac{12}{m^2-9}+\dfrac{2}{m+3} , the result is

  1. ×

    \dfrac{6}{m^2-9}

  2. ×

    \dfrac{2}{m-3}

  3. ×

    \dfrac{2}{m+3}

  4. ×

    \dfrac{2m+6}{m^2-9}

Steven Zheng Steven Zheng posted 4 months ago


Answer

  1. \dfrac{12}{m^2-9}+\dfrac{2}{m+3}

    =\dfrac{12+2m-6}{m^2-9}

    = \dfrac{2(m+3)}{m^2-9}

    =\dfrac{2}{m-3}

Steven Zheng Steven Zheng posted 4 months ago

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