I, II, and III

same as explanation in D. N must not be odd numbers.

III is not true

First, recall that a prime number is only divisible by itself and 1, and that 1 is not a prime number. So, statement I must be true, since a number that can be divided by different prime numbers p and q can’t be prime.

Therefore I is true.

Every number can be written as a product of a particular bunch of prime numbers. For this statement.

N = \dots \cdot p\cdot q = \dots (pq)

Therefore

N must be divisible by pg

II statement is true

Based on the exaplnation above, I and II only

I and III only

Recall 6 can be divisible by prime two numbers 2 and 3. So N must not be odd numbers.

III is not true