Question
Solve the equation with square root coefficient
a^3+2\sqrt{7}a^2+7a+\sqrt{7}+1 =0
Solve the equation with square root coefficient
a^3+2\sqrt{7}a^2+7a+\sqrt{7}+1 =0
Let
b = \sqrt{7}
then
b^2 = 7
The equation is transformed to
a^3+2ba^2+b^2a+b+1 = 0
Rearrange the terms to make the equation a quadratic equation in terms of b
ab^2+(2a^2+1)b+a^3+1 = 0
Factorizing the terms
ab^2+(2a^2+1)b+(a+1)(a^2-a+1) = 0
Cross-multiply the coefficients of terms for factorization
\begin{array}{cc} a & a^2-a+1 & a^2-a+1 \\ 1 & a+1 & a^2+a\\ \hline & & 2a^2+1 \end{array}
Then the equation is factored to
(ab+a^2-a+1)(b+a+1) = 0
Then
or
From (2), we get
a = -(b+1) = -(\sqrt{7}+1 )
Now we evaluate equation (3). Substitute b=\sqrt{7} into the equation
a^2+(\sqrt{7}-1 )a+1=0
The discriminant
\Delta = (\sqrt{7}-1)^2-4
=(\sqrt{7}-3 )(\sqrt{7}+1 )
=(\sqrt{7}-\sqrt{9} )(\sqrt{7}+1 )<0
Therefore
There is no real root for the quadratic equation
In summary,
the equation a^3+2\sqrt{7}a^2+7a+\sqrt{7}+1 =0 has one real root -\sqrt{7}-1